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(D) First,calculate the sum of $\frac{1}{4}$ and $\frac{1}{5}$:$\frac{1}{4} + \frac{1}{5} = \frac{5+4}{20} = \frac{9}{20} = 0.45$.Subtract this sum fr

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$\left(\frac{200}{11}\right) \%$

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(D) First,calculate the sum of $\frac{1}{4}$ and $\frac{1}{5}$:$\frac{1}{4} + \frac{1}{5} = \frac{5+4}{20} = \frac{9}{20} = 0.45$.Subtract this sum from unity $(1)$:$1 - 0.45 = 0.55$.This is the correct answer.The boy's answer is $0.45$.The error is $|0.55 - 0.45| = 0.10$.The percentage error is calculated as:$	ext{Percentage Error} = \left( \frac{	ext{Error}}{	ext{Correct Value}} ight) 	imes 100$$= \left( \frac{0.10}{0.55} ight) 	imes 100$$= \left( \frac{10}{55} ight) 	imes 100 = \left( \frac{2}{11} ight) 	imes 100 = \frac{200}{11} \%$.

$A$ boy found the answer for the question "subtract the sum of $\frac{1}{4}$ and $\frac{1}{5}$ from unity and express the answer in decimals" as $0.45$. The percentage of error in his answer was

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